Question about C=0 Zero Acceptance Number Sampling Plan

[vphan27]

My company is using the following sampling table based on Nicholas Sequigla's Zero Acceptance Number Sampling Plan:

http://guidebook.dcma.mil/226/tools_links_file/stat-sample.htm

My question is where do the sampling size numbers in the table come from? What statistics equation/formula is used to arrive at these sampling size numbers? How is this statistics formula used to get these numbers?

I have read that the numbers may come from Hypergeometric distribution, Poisson distribution, or Binomial distribution. I have tried applying these formulas but still do not understand how they got the numbers in the table.

For example, the table states that for a lot size of 51 to 90 and AQL of 1%, the sample size is 13. My question is how was it determined that 13 is the sufficient sample size? There must be a statistics formula used to calculate this 13.

If someone can proivde me with a thorough explanation, I would truly appreciate it.

 

[cloa]

Have you looked through this?

http://books.google.com/books?id=Ow...ce=gbs_ge_summary_r&cad=0#v=onepage&q&f=false

 

[vphan27]

I have come across this book during my research on this topic over the internet. Do you have a copy of this book and does it explain how the numbers in the table are calculated?

 

[prdave00]

The probability of acceptance and associated AQL level (or index) are based on operating characteristic (OC) curves generated using a hypergeometric distribution allowing for no defects for a given lot and sample size. Googling "hypergeometric" and "sampling" should provide more information on generating the OC curve. For example,

http://mathdl.maa.org/mathDL/4/?pa=content&sa=viewDocument&nodeId=428&pf=1.

If you are using the c=0 sampling plan, then you really should have buy Squeglia's book to cross reference.