amer015
Mechanical
- Dec 19, 2012
- 12
Hi there, i'm looking for some help to calculate the COP of a chiller (low pressure chiller) based on the pressure of the refrigerant that i have inside the Evaporator and the Condsenser.
the problem is i'm getting a very high COP when i'm doing the calculation, please find below the procedure:
1) h1= enthalpy of the Vapor after the evaporator (based on the presuure inside the evaporator pe)
2) h2= enthalpy of the vapor after the compressor( based on the pressure inside the condensor Pc and entropy s2 as s1=s2)
3) h3= enthalpy of the liquid refrigerant after the condensor( based on the pressure of the refrigerent)
4) h4=h3
pe=0.043 MPa
pc=0.152 MPa
COP=(h1-h4)/(h2-h1)
this is how we used to calculate the COP at the university, following the same procedure and we used to do it for R134 not for R123.
is there something that i don't know about R123 properties!
Regards
the problem is i'm getting a very high COP when i'm doing the calculation, please find below the procedure:
1) h1= enthalpy of the Vapor after the evaporator (based on the presuure inside the evaporator pe)
2) h2= enthalpy of the vapor after the compressor( based on the pressure inside the condensor Pc and entropy s2 as s1=s2)
3) h3= enthalpy of the liquid refrigerant after the condensor( based on the pressure of the refrigerent)
4) h4=h3
pe=0.043 MPa
pc=0.152 MPa
COP=(h1-h4)/(h2-h1)
this is how we used to calculate the COP at the university, following the same procedure and we used to do it for R134 not for R123.
is there something that i don't know about R123 properties!
Regards