JJAV1983
Mechanical
- Nov 7, 2012
- 35
Hello All,
Is there a way to calculate the maximum separation distance between rack and pinion under load?
Total load on Rack:
L= 85000 lb
PD= 6.928 Pitch Diameter of Pinion
No.Teeth=22
n= 6 number of pinions
PA= 20 pressure angle
ho= distance from back face to pitch line of rack = 2.81 in
Force per pinion Ft=L/n = 14166.667 lb (tangential)
Torque required at pinion: (Ft*PD/12)= 8178 ft-lb
Separating Force= Ft*tan= 5156.245 lb
Taking into account that the Diametral Pith is 3.175 in, from we have that:
For a 20 degree pressure angle: The change in center distance= 1.374 x change in backlash= 1.374 x .012475 (value interpolated from link above) = .017 in"
I have determined the pinion and gear center distance as; 5.959 in. HOW DO WE DETERMINE THE MAXIMUM SEPARATING DISTANCE WHEN THE PINION IS UNDER LOAD? (in order to keep the set engaged)
Your help will be much appreciated.
Thank you,
JJAV
Is there a way to calculate the maximum separation distance between rack and pinion under load?
Total load on Rack:
L= 85000 lb
PD= 6.928 Pitch Diameter of Pinion
No.Teeth=22
n= 6 number of pinions
PA= 20 pressure angle
ho= distance from back face to pitch line of rack = 2.81 in
Force per pinion Ft=L/n = 14166.667 lb (tangential)
Torque required at pinion: (Ft*PD/12)= 8178 ft-lb
Separating Force= Ft*tan= 5156.245 lb
Taking into account that the Diametral Pith is 3.175 in, from we have that:
For a 20 degree pressure angle: The change in center distance= 1.374 x change in backlash= 1.374 x .012475 (value interpolated from link above) = .017 in"
I have determined the pinion and gear center distance as; 5.959 in. HOW DO WE DETERMINE THE MAXIMUM SEPARATING DISTANCE WHEN THE PINION IS UNDER LOAD? (in order to keep the set engaged)
Your help will be much appreciated.
Thank you,
JJAV