leakyseal
Chemical
- Oct 29, 2007
- 27
Hi folks,
I've been asked to assist with some design which is a bit beyond my experience and I keep getting trapped in some circular thinking -- I'm hoping someone can help me sound this out a bit.
An existing process tank contains a hydrocarbon below its boiling temperature. The tank is currently protected with a conservation vent and a rupture disk. In the interest of minimizing the organic vapours that exit the conservation vent, we have been asked to install a condenser at the top of the tank to capture the vapours and return them to the tank. We've tentatively selected a fairly vanilla shell and tube with cooling tower water on the shell. Sizing assumes that the solvent is at its boiling point to provide a conservative vapourization (and hence, condensation) requirement, but in practice the solvent will not boil and the vap gen rate will be lower than the design point.
The client asked us to size the exchanger "in isolation", but we are now being asked to review the proposed installation. Here's where my befuddlement starts. For some reason they want the vapor subcooled, and have piped it up to have the vapor enter the top of the vertically mounted exchanger, and drip condensate back into the vessel. First problem is that there's nothing preventing the vapour from entering the "downstream" side of the exchanger. I assume this may be addressable with some kind of thermostatic valve to block the upward flow of vapour but allow the downstream flow of condensate (similar to a steam trap).
My concern is ensuring that the vapour preferentially goes into the condenser rather than through the conservation vent. The cons vent is set to crack at 10" wc. It seems to me that if the pressure drop through the condenser is less than this (and the condensation rate exceeds the net vapour gen rate) then we'll be okay. If this assumption is reasonable, I want to make sure I'm thinking about the pressure drop appropriately.
I've determined the pressure drop per unit length of pipe under the flowing vapour condition, and (inlet pipe loss + hx loss) is less than 10" wc. All good. BUT: how do I properly account for the elevation changes? Pipe inlet and outlet at the vessel head are both at the same elevation. Vapour is heavier than air, so the inlet leg elevation loss is calc'd via (rho-vap)gh?. Condensate volume will be quite small relative to vapour volume and is falling under gravity through an unflooded pipe (notwithstanding the condensate trap...hey, it just occured to me, can we just P-trap the piping?)...so how the heck do I calculate the head "gain" on the discharge side?
I'm not as boneheaded in real life as this may make me appear, honest. Any feedback (assuming any meaning can be teased out of this) would be greatly appreciated. Thanks!
I've been asked to assist with some design which is a bit beyond my experience and I keep getting trapped in some circular thinking -- I'm hoping someone can help me sound this out a bit.
An existing process tank contains a hydrocarbon below its boiling temperature. The tank is currently protected with a conservation vent and a rupture disk. In the interest of minimizing the organic vapours that exit the conservation vent, we have been asked to install a condenser at the top of the tank to capture the vapours and return them to the tank. We've tentatively selected a fairly vanilla shell and tube with cooling tower water on the shell. Sizing assumes that the solvent is at its boiling point to provide a conservative vapourization (and hence, condensation) requirement, but in practice the solvent will not boil and the vap gen rate will be lower than the design point.
The client asked us to size the exchanger "in isolation", but we are now being asked to review the proposed installation. Here's where my befuddlement starts. For some reason they want the vapor subcooled, and have piped it up to have the vapor enter the top of the vertically mounted exchanger, and drip condensate back into the vessel. First problem is that there's nothing preventing the vapour from entering the "downstream" side of the exchanger. I assume this may be addressable with some kind of thermostatic valve to block the upward flow of vapour but allow the downstream flow of condensate (similar to a steam trap).
My concern is ensuring that the vapour preferentially goes into the condenser rather than through the conservation vent. The cons vent is set to crack at 10" wc. It seems to me that if the pressure drop through the condenser is less than this (and the condensation rate exceeds the net vapour gen rate) then we'll be okay. If this assumption is reasonable, I want to make sure I'm thinking about the pressure drop appropriately.
I've determined the pressure drop per unit length of pipe under the flowing vapour condition, and (inlet pipe loss + hx loss) is less than 10" wc. All good. BUT: how do I properly account for the elevation changes? Pipe inlet and outlet at the vessel head are both at the same elevation. Vapour is heavier than air, so the inlet leg elevation loss is calc'd via (rho-vap)gh?. Condensate volume will be quite small relative to vapour volume and is falling under gravity through an unflooded pipe (notwithstanding the condensate trap...hey, it just occured to me, can we just P-trap the piping?)...so how the heck do I calculate the head "gain" on the discharge side?
I'm not as boneheaded in real life as this may make me appear, honest. Any feedback (assuming any meaning can be teased out of this) would be greatly appreciated. Thanks!