VTer
Electrical
- Dec 23, 2008
- 240
Hi All,
I saw a reference that "When the load cycle is sufficiently short so that the temperature of the transformer does not change appreciably during the
cycle, the minimum transformer size is the rms value of the load."
The equation that is provided is S=sqrt((S1^2*t1+S2^2*t2)/t(cycle))
For example: S1=100kVA for 2 min, S2=50kVA for 2min total cycle time is 4 min.
Using the above equation the resultant min transformer size is 79kVA.
My question is, why the need to perform RMS of the load which is already a resultant value of RMS current and voltage? Why not just take the average value which in this case would be 75kVA?
"Throughout space there is energy. Is this energy static or kinetic! If static our hopes are in vain; if kinetic ù and this we know it is, for certain ù then it is a mere question of time when men will succeed in attaching their machinery to the very wheelwork of nature". û Nikola Tesla
I saw a reference that "When the load cycle is sufficiently short so that the temperature of the transformer does not change appreciably during the
cycle, the minimum transformer size is the rms value of the load."
The equation that is provided is S=sqrt((S1^2*t1+S2^2*t2)/t(cycle))
For example: S1=100kVA for 2 min, S2=50kVA for 2min total cycle time is 4 min.
Using the above equation the resultant min transformer size is 79kVA.
My question is, why the need to perform RMS of the load which is already a resultant value of RMS current and voltage? Why not just take the average value which in this case would be 75kVA?
"Throughout space there is energy. Is this energy static or kinetic! If static our hopes are in vain; if kinetic ù and this we know it is, for certain ù then it is a mere question of time when men will succeed in attaching their machinery to the very wheelwork of nature". û Nikola Tesla