Sheet metal - Configuration Specific K_Factor

[CADone]

Hi,
I have 2 configurations of a bent sheetmetal part.
My question : How can I have different K-FActor values for these 2 configs?

Any help on this is appriciated.

Thanks
Mohan

 

[SBaugh]

I don't think you can... since the K-factor is hard-coded into the sheet metal feature... You might try a Bend table... but other then that I don't see away.

Regards,

Scott Baugh, CSWP

http://www.scottjbaugh.com

"If it's not broke, Don't fix it!"

faq731-376

 

[AnnaWood]

That is a limitation in SW. Be sure to put in an Enhancement Request for K-Factor to be configuarable.

https://www.solidworks.com/pages/services/subscription/enhancements/index.html

Cheers,

Anna Wood
SW 2007 SP4.0, WinXP
Dell Precision 380, Pentium D940, 4 Gigs RAM, FX3450

http://designsmarter.typepad.com/solidmuse

http://www.phxswug.com

 

[J-C]

There is a K-Factor bend table but I've never been able to get it to work. Help only mentions it but doesn't tell how to format it. The Excel file is in the SolidWorks folder but it needs to be filled out.

Jason

SolidWorks 2007 SP5.0
SolidWorks 2008 SP0.1
WinXp sp2 (32 and 64 bit)

 

[bearly]

It is possible to modify the sheet metal k-factor bend table, but only if the radius / thickness is different between configurations. If it is, then simply put the ratio in one of the columns of the bend table.
For instance, if you are using 7 ga. steel in one configuration and 7 ga. stainless in the other then you just take the ratio of a bend radius (say--.125") to 7 ga. steel thickness (.1793") , which would be .6972, and put that in one column. Then you take the ratio of a bend radius (say also --.125") to 7 ga. stainless thickness(.1875") , you get .6667, and put that in another column. The columns need to be ordered in ascending order from left to right.
If this is practical to do for all the possible configurations and you don't risk having the exact same thickness and bend radius for two different configurations that you would like to assign different k-factors to, then this may work for you. Good luck.

Brian