P1ENG
Structural
- Aug 25, 2010
- 237
I frequently specify fillet and groove welds, but plug welds are a little foreign to me yet so bear with me. Base material is HRS steel of nominal thickness.
AWS A2.4:2012 Section 9.2 says: "Plug weld size is the diameter of the hole at the faying surface."
AWS D1.3:2008 Section 2.2.6 says: "Arc plug welds (see figure 2.6) shall be specified as the minimum effective diameter at the faying surface (de)."
As I understand figure 2.6, the actual diameter of the hole in the member being attached is of no concern as long as the minimum diameter of 2.3.7.2 is met.
So real world application: There are 1/2" holes in 11 GA (0.120") material for plug welding. 1/2" meets the minimum required hole size per 2.3.7.2. Solving for the visible diameter, d, using de = 0.375" [minimum allowed] and the equation found in Figure 2.6 (de = 0.7d-1.5t), the minimum visible diameter of the weld needs to be 0.793". So what size should the plug weld be in the symbol: 13/16, 1/2, 3/8, or 1/2 (3/8)? Since the visible weld size needs to be 0.793", how is the welder supposed to know this?
If the hole is filled only to the size of the hole (i.e. the visible diameter of weld is the same size as the hole), then calculating for de gives a value less than the allowed minimum of 3/8".
Juston Fluckey, SE, PE, AWS CWI
Engineering Consultant
AWS A2.4:2012 Section 9.2 says: "Plug weld size is the diameter of the hole at the faying surface."
AWS D1.3:2008 Section 2.2.6 says: "Arc plug welds (see figure 2.6) shall be specified as the minimum effective diameter at the faying surface (de)."
As I understand figure 2.6, the actual diameter of the hole in the member being attached is of no concern as long as the minimum diameter of 2.3.7.2 is met.
So real world application: There are 1/2" holes in 11 GA (0.120") material for plug welding. 1/2" meets the minimum required hole size per 2.3.7.2. Solving for the visible diameter, d, using de = 0.375" [minimum allowed] and the equation found in Figure 2.6 (de = 0.7d-1.5t), the minimum visible diameter of the weld needs to be 0.793". So what size should the plug weld be in the symbol: 13/16, 1/2, 3/8, or 1/2 (3/8)? Since the visible weld size needs to be 0.793", how is the welder supposed to know this?
If the hole is filled only to the size of the hole (i.e. the visible diameter of weld is the same size as the hole), then calculating for de gives a value less than the allowed minimum of 3/8".
Juston Fluckey, SE, PE, AWS CWI
Engineering Consultant