Simple (dumb) question regarding weld design

[ColinPearson]

Hey folks.
For whatever reason, weld sizing has always been kind of unclear to me. I'm using ASD in the red (14th) Steel Manual and have a couple questions:
1) EQ.8-5b and EQ.8-8b states that they calculates the "shear per linear inch" due to concentric load and moment; I take it that these values would have units of FORCE/LENGTH. Fair enough, but then EQS.8-9b, 8-10b and 8-11b calculate the "resultant force" which I take to mean a value with units of FORCE. They appear to have the same basic form so I'm wondering what units the results of EQS.9/10/11 are actually in?

2) I'm assuming that with EQS.9/10/11, I'm actually getting a result in a FORCE/LENGTH unit. It sounds stupid, but how do I then compare that to an allowable force as calculated by following Chapter J and Table J2.5? Is it as simple as multiplying my resultant FORCE/LENGTH value from EQ.8-11b by the length of weld and comparing that to the available strength? Alternatively, in calculating the available strength (0.60*Fexx*Ae), I guess I could use a unit length in the effective weld area and then I'm calculating the available strength per linear unit length which I can compare directly to the results of EQ-11b.

Thanks in advance and have a great day!

 

[desertfox]

Hi

I haven’t got access to the reference you are talking about however if your weld strength is units of force/length then yes just multiply that figure by the length of the actual weld.

“Do not worry about your problems with mathematics, I assure you mine are far greater.” Albert Einstein

 

[ColinPearson]

Thank you !