Boltzie
Structural
- Mar 15, 2005
- 2
I'm designing a soldier pile retaining wall for an already failed location. I understand the design and have done a few soldier pile designs for excavation, but I believe this case is a little different. I have the following questions:
1. Should I be using Ka or Ko for the active earth pressure? (Am I just adding some safety factor by using Ko?)
2. How does the design/earth pressures differ when a slip plane has already occurred? The state DOT engineer does not want to excavate out the failed material, just drill/place piles and excavate failed material.
3. What is the typical procedure when using sheet piling or soldier piles & lagging at an existing slope failure? (excavate material, place and compact new behind wall, etc.)
4. How does the design differ when the piles/holes are socketed 5' to 10' into the rock strata? (typically, the concrete is placed to the dredge/lower level. Not sure how many new unknowns I'm adding by adding a new boundary condition (fixed) at the base.)
5. How do the applied loads change when the actual embedded depth is much larger than the calculated depth, D? Am I just increasing the safety factor by embedding more? Do I need to recalculate the applied loads when actual 'D' is much deeper than required 'D'?
Thanks in advance.
1. Should I be using Ka or Ko for the active earth pressure? (Am I just adding some safety factor by using Ko?)
2. How does the design/earth pressures differ when a slip plane has already occurred? The state DOT engineer does not want to excavate out the failed material, just drill/place piles and excavate failed material.
3. What is the typical procedure when using sheet piling or soldier piles & lagging at an existing slope failure? (excavate material, place and compact new behind wall, etc.)
4. How does the design differ when the piles/holes are socketed 5' to 10' into the rock strata? (typically, the concrete is placed to the dredge/lower level. Not sure how many new unknowns I'm adding by adding a new boundary condition (fixed) at the base.)
5. How do the applied loads change when the actual embedded depth is much larger than the calculated depth, D? Am I just increasing the safety factor by embedding more? Do I need to recalculate the applied loads when actual 'D' is much deeper than required 'D'?
Thanks in advance.