jeb6294
Civil/Environmental
- Mar 6, 2006
- 6
Here's the situation...got a lake adjacent to the property were designing with an existing spillway structure. I am trying to come up with some calculations showing that the spillway and outlet pipes will be fine with our additional development.
For simplicity sake, the spillway is basically shaped like a capital "D". The curve of the "D" is at water level and is 39.77-ft in length. The straight portions ("[" this part of the "D") are 1-ft. above water level and total 45-ft in length. The whole thing dumps into a pair of 90-in pipes. We're doing a stage-discharge up to 10.3-ft above water level.
The big question is how to go about figuring the flow these outlet pipes are going to see.
1) use the standard Q=cLH^1.5 with L=39.77 for the first foot and then L=45+39.77 for the rest?
2) I found something sorta similar in my Gupta book about a shaft spillway that's based on a vertical pipe with a flared end. It says for a shaft spillway to treat the first part of the flow as weir flow (Q=cLH^1.5), then switch to orifice flow (Q=CA(2gH)^0.5), and finally to pipe flow (Q=A(2gh/K)^0.5) once the whole thing is submerged.
3) Something else I haven't thought of.
For simplicity sake, the spillway is basically shaped like a capital "D". The curve of the "D" is at water level and is 39.77-ft in length. The straight portions ("[" this part of the "D") are 1-ft. above water level and total 45-ft in length. The whole thing dumps into a pair of 90-in pipes. We're doing a stage-discharge up to 10.3-ft above water level.
The big question is how to go about figuring the flow these outlet pipes are going to see.
1) use the standard Q=cLH^1.5 with L=39.77 for the first foot and then L=45+39.77 for the rest?
2) I found something sorta similar in my Gupta book about a shaft spillway that's based on a vertical pipe with a flared end. It says for a shaft spillway to treat the first part of the flow as weir flow (Q=cLH^1.5), then switch to orifice flow (Q=CA(2gH)^0.5), and finally to pipe flow (Q=A(2gh/K)^0.5) once the whole thing is submerged.
3) Something else I haven't thought of.