Does anyone know the formula for finding the weight of a spiral lockseam duct? I have been looking online for a day, but I can only find weight charts, but not the actual formula. I'm trying to find the Lb/Ft for my company because I think that our weights are wrong. The attachment is a drawing of the lateral section of spiral lockseam pipe.
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Spiral Duct Weight
- Thread starter Zimmy242
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LittleInch
Petroleum
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Remember - More details = better answers
Also: If you get a response it's polite to respond to it.
- Thread starter
- #3
I'm sorry if I didn't get a chance to respond. It's been hectic around here.
I know the steel is 5.395" wide coils.
I also know that the nominal weights are:
24 Ga. - .0276"
22 Ga, - .0336"
I would like the formula to be able to be changed for several diameters.
LittleInch
Petroleum
First off figure out for each nominal length how much more steel is used in those seams.
This will give you a multiplier for the unit length you choose (ft or metre)
Then its Pi x D x thickness x density of steel x multiplier.
Note your "weights" are in fact thickness of pipe. Pretty thin!
Spiral might add a bit more but not much. Depends on the angle of the seam relative to axis of pipe. maybe add another 5%.
How far out are you from the catalogue - they SHOULD know better than you.
Remember - More details = better answers
Also: If you get a response it's polite to respond to it.
This will give you a multiplier for the unit length you choose (ft or metre)
Then its Pi x D x thickness x density of steel x multiplier.
Note your "weights" are in fact thickness of pipe. Pretty thin!
Spiral might add a bit more but not much. Depends on the angle of the seam relative to axis of pipe. maybe add another 5%.
How far out are you from the catalogue - they SHOULD know better than you.
Remember - More details = better answers
Also: If you get a response it's polite to respond to it.
- Thread starter
- #5
LittleInch
Petroleum
Can't work that out.
Should be
3.142 x D x T x 0.28 x 1.15 x 1.05
The coil to length ratio is 1.15, the extra length for the spiral I reckon is 1.05.
All in inches, give you lb per linear foot.
How does that work?
Remember - More details = better answers
Also: If you get a response it's polite to respond to it.
Should be
3.142 x D x T x 0.28 x 1.15 x 1.05
The coil to length ratio is 1.15, the extra length for the spiral I reckon is 1.05.
All in inches, give you lb per linear foot.
How does that work?
Remember - More details = better answers
Also: If you get a response it's polite to respond to it.
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