EddieM
Mechanical
- Sep 2, 2002
- 1
I am having difficulty understanding the Section 6.2.6.2 “Short Term Conditions in the 62.1-2004 Standard”. The following is a theoretical example for a situation that I think might be addressed by this section:
School Gym being used Saturday night for a basketball game.
Dimensions 50 ft wide x 100 ft long x 20 ft high for a volume of 100,000 cf.
Occupancy = 1,000 people
Vbz = 10,000 cfm (a made-up number)
Per the standard’s formula 6-9a, I calculate a time, T, of 30 minutes.
The question is that now that I have the time, what do I do with it? Optional provision one says that for zones with fluctuating occupancy, “The zone population may be averaged over time T.”
If a game normally lasts 2 hours (the only use of the gym in a 24 hour Saturday or 48 hours if we assume the gym is not used again until school opens on Monday), how does time, T apply? What does it mean when it says "The zone population may be averaged over time T"?
Any help would be greatly appreciated.
School Gym being used Saturday night for a basketball game.
Dimensions 50 ft wide x 100 ft long x 20 ft high for a volume of 100,000 cf.
Occupancy = 1,000 people
Vbz = 10,000 cfm (a made-up number)
Per the standard’s formula 6-9a, I calculate a time, T, of 30 minutes.
The question is that now that I have the time, what do I do with it? Optional provision one says that for zones with fluctuating occupancy, “The zone population may be averaged over time T.”
If a game normally lasts 2 hours (the only use of the gym in a 24 hour Saturday or 48 hours if we assume the gym is not used again until school opens on Monday), how does time, T apply? What does it mean when it says "The zone population may be averaged over time T"?
Any help would be greatly appreciated.
