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Standard Definition of Displacement. Is there one?

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KevinK2

Mechanical
Feb 6, 2012
119
I searched and could not find an ASTM, ASME, SAE, or DIN standard defining displacement.

My research lead me back to early "piston pumps" (predating steam engines). There displacement was defined as # of pistons x piston displacement, as these pumps worked on a 1 rev cycle.

I think this method was copied by the otto cycle engines, even though they needed 2 revs to complete a cycle.

When 2 cycle engines appeared, the same "piston pump" approach to displacement was used, but these engines need just one rev to complete all cycles. This advantage was handled in motorcycle racing by allowing about 50-70% more displacement for the 4 stroke bikes, that competed against the 2 stroke bikes.

With the 2 and 4 stroke engines, the "piston pump" rule could always be substantiated by considering each engine as a 1 rev pump to verify displacement.

Enter the Wankel.

The "1.3L" engine found today in Mazdas was very different, with dynamic combustion chambers, and 3 revs to complete a single chambers's 4 strokes. The developers apparently used a different rule to get displacement. They said you have 2 rotors, and each rotor fires once PER REV, a fired chamber is .64L, so displacement is 2 rotors x .64L per rotor = 1.3L displacement ... PER REV.

With this logic, and rotor = piston, a 2 stroke would have the correct displacement (per rev) for 100% efficency. The 4 stroke 5.0L engine would be 2.5L, based on Wankel's "1 rev" method. This is actually a good way to determine displacement, as it is consistent for all engines; 100% VE ingestion per rev.

I don't think anyone is prepared to call their 5.0 V8 a 2.50. So, if one were to apply the "piston pump" rule to the Wankel:

Each rotor has 3 distinct combustion chambers per rotor, that take 3 output shaft revs to fire. With 2 rotors, that's 3.8L fired in 3 revs.

As a wankel pump, each of the sets of 4-otto-cycles of a combustion chamber cycle, provide 2 pumping cycles for a pump (note that the valving and porting are ignored in the basic "piston pump" displacemnt calc). So you take 2 x the fired chambers (pumping strokes) and divide by 3 to get one rev, and you have 2.6L displacement rating, per the "piston pump" method. This is actually the number of chambers that fire in 2 revs, and is an equal basis for rating the extremely common 4 stroke piston engine.

Other than the "piston pump" method, is there any official standard for displacement?

Kevin
 
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I always thought it was stroke times bore times number of pistons. Maybe I have been wrong all these long years??
 
That is the "piston pump" method I described, if you think about it.
 
Actually it's piston area times stroke times number of pistons. Piston area (for round cylinders, yes Honda made oval ones) is pi*radius^2.

But you knew that.

The only question is what is the displacement of a rotary. I've always considered it to be 3.9 liters.

----------------------------------------

The Help for this program was created in Windows Help format, which depends on a feature that isn't included in this version of Windows.
 
There is no single method that would keep everybody happy. So each user defines it the way they want to, to suit their purposes and prejudices.





Cheers

Greg Locock


New here? Try reading these, they might help FAQ731-376
 
I agree with Greg.

To be pedantic about it, if you change it for average ingestion per full cycle instead of per induction stroke, how do you account for superchargers?

Regards
Pat
See FAQ731-376 for tips on use of eng-tips by professional engineers &
for site rules
 

Super chargers and turbos are beyond the scope of my question, but you'd start with pressure ratio and lots of corrections for shaft work done, and back pressure, and intercooling, etc.

Apparently the answer is no standard for disp't rating.

The Mazda wankel is, assuming 100% VE:

1.3L ... based on air injested in 1 rev.
3.8L ... based on one complete engine cycle of 3 revs.
2.6L ... based on the "piston pump" type rating I used.

For common NA engines, the ancient "piston pump" rating method is correct for all but the 2-stroke, which is a well known error, at least in the motorcycle racing world.

Kevin

 
Greg said:
"Well thanks for that, but I must be off, my grandmother has found some eggs and lost her dentures."

Translation?
 
If you really must know. Translation.
""Do not teach your grandmother how to suck eggs""

The good engineer does not need to memorize every formula; he just needs to know where he can find them when he needs them. Old professor
 
@ Greg, LOL.

In my 'day' or notebook, or whatever you want to say displacement is total swept volume.
Swept volume being the_swept_volume, x amount of cylinders = displacement.

Thats the most standard definition of displacement you can get which is fine for 98% of the time. The other 2% depends.

''Other than the "piston pump" method, is there any official standard for displacement?''

Wiki>


Engineering
''Engine displacement'', the total volume of air/fuel mixture an engine can draw in during one complete engine cycle.

Take what you want from that I guess.


''assuming 100% VE''

Thats in with the 2% I mentioned above.

Brian,
 
Actually it displaces it's swept volume, but the density of the air changes with VE.

Regards
Pat
See FAQ731-376 for tips on use of eng-tips by professional engineers &
for site rules
 
This whole issue was really stirred up by the likes of Norton and Mazda, competing in limited capacity racing, running a n engine whose capacity could never really be compared to the conventional engines.

- Steve
 
Berkshire said:
""Do not teach your grandmother how to suck eggs"" .... If that is supposed to be a slam on me, I don't see the reason, and it sounds like someone thinks they are very special, at least in their head.

"The good engineer does not need to memorize every formula; he just needs to know where he can find them when he needs them." Old professor

Politely disagree. I relied on the principles of Physics and related formulas which were burned in my cpu from school, not memorization, to save millions of dollars for the company I worked for. This quote would say the good engineers were the ones I saw going to the ME PE test with shopping carts full of books, and I was the bad engineer who went to the test with 3 books, left early, and passed with an 87 or 88%. Sorry Brian, no LOL for Greg from me.


 
Part of the reason I brought this up was to see if an engineering standard could help define the displacement of a Wankel. Number of pistons and swept volume put a Mazda 13B, with 6 chambers at .64L each at 3.8L, vs the 1.3L published size. many owners think it's rated the same as a V8, and boast about the high specific power.

Since it takes 3 revs to fire all 6 chambers, it can be visualized as equivelant to a 3.8L 6 cyl engine, with a .667 gear reduction at the original output shaft. This provides the same otto cycle graph for each chamber, vs revs, for the 6 cylinder engine and the wankel.
 
FWIW, most racing sanctioning bodies class the Mazda 1.3L wankel as a 2.6L, presumably using the pump method. This tends to work fairly well for classing purposes, as a 2.6L 4-banger will be similar in output.
 
"you'd start with pressure ratio and lots of corrections for shaft work done, and back pressure, and intercooling, etc."

Pretty soon you are talking shaft hp, and with fuel flow numbers, BSFC, or hp/pound, or in other words...real numbers.
 
btrueblood said:
Pretty soon you are talking shaft hp, and with fuel flow numbers, BSFC, or hp/pound, or in other words...real numbers.

Not me, just looking for a standard for rated displacement, and found none, and unfortunately found one low class remark. I'll stick with the ancient "piston pump" method I unearthed before. All piston engines on the road are correctly sized, except the 2-strokes are still undersized, and the 13B goes from 1.3L to 2.6L.

You don't see existing engines rated displacement, diesel or gas, a function of turbos and/or pulley driven superchargers.


 
When cars start taking power from the turbine, they become gas turbine vehicles. What's the "swept capacity" of a tiny ICE as part of a gas turbine?

- Steve
 
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