jorgemoreno
Electrical
- Sep 1, 2002
- 20
Hi everyone,
I have an unusual application in wich I need one Output (OUT1) and two input signals (IN1 and IN2)in a circuit, the input signals will provide +V (+24V) or will be open (lead lifted not grounded) depending on certain conditions:
1. IN 1 = +V, when this happen a Step Up voltage ramp is generated at a rate of 1V/sec until it reaches +10 V approximately, when IN 1 is not longer applied with +V (input open) the voltage reached (+10V) must remain until the input conditions change.
2. IN 2 = +V, when this happen a Step Down voltage ramp is generated at a rate of 1V/sec until it reaches 0V, when IN 2 is not longer applied with +V (input open) the voltage reached (0)V must remain until the input conditions change.
I have experimented with a circuit using a PNP bipolar transistor arranged as a constant current source charging a Capacitor (IN1), this gives me the step up ramp with no problem at 1V/sec, the inconvenience of this is that I have to provide negative voltage on transistor base to operate it, this obligates me to use a negative source on the application which means to add more investment and circuitry. Besides when trying to dicharge the capacitor using a second transistor (NPN)as IN2 the step down ramp does not act in the same way as the ramp up, the difference is the time constant even I am using same resistor values.
If someone could help me to find out this application I will be really grateful.
Thanks
Jorge
I have an unusual application in wich I need one Output (OUT1) and two input signals (IN1 and IN2)in a circuit, the input signals will provide +V (+24V) or will be open (lead lifted not grounded) depending on certain conditions:
1. IN 1 = +V, when this happen a Step Up voltage ramp is generated at a rate of 1V/sec until it reaches +10 V approximately, when IN 1 is not longer applied with +V (input open) the voltage reached (+10V) must remain until the input conditions change.
2. IN 2 = +V, when this happen a Step Down voltage ramp is generated at a rate of 1V/sec until it reaches 0V, when IN 2 is not longer applied with +V (input open) the voltage reached (0)V must remain until the input conditions change.
I have experimented with a circuit using a PNP bipolar transistor arranged as a constant current source charging a Capacitor (IN1), this gives me the step up ramp with no problem at 1V/sec, the inconvenience of this is that I have to provide negative voltage on transistor base to operate it, this obligates me to use a negative source on the application which means to add more investment and circuitry. Besides when trying to dicharge the capacitor using a second transistor (NPN)as IN2 the step down ramp does not act in the same way as the ramp up, the difference is the time constant even I am using same resistor values.
If someone could help me to find out this application I will be really grateful.
Thanks
Jorge