Susanp,
The voltage is needed to give you the wattage consumed. Note that the loads are generally expressed in Volt-Amperes, VA, and the wattage is a function of this and the power factor noted by the other posts. But looking at the values given, lets say the feed to this unit is at 208V/3phase. The compressor would be 3-ph and the condenser fans would be single phase in most cases. The locked rotor amparage you gave of 266 amps is not for loading, it is for calculating the starting current requirements. So at 208V, you have:
63.6A x 208V x SQRT3 = 22896 VA or 22.9 kVA
2 @ 4.3A x 208V/1ph = 1789 VA or 1.8 kVA
1 @ 3.7A x 208V/1ph = 770 VA or 0.8 kVA
_______
Total Load = 25.5 kVA
At a reasonable Power Factor of 0.85= 21.7 kW
Other numbers you will see are the MCA, minimum circuit amps which is 125% of the largest load plus the rest, in this case this would be 79.5A + 7.2A = 86.7A. Also the MOCP, which is the Max OverCurrent Protection allowed which adds the largest load on top of this figure which would be 150.3 Amps. So for this unit, I would select a breaker and feeder of between 100A and 125A, depending on load profile, start stop requirements, etc....
If of course your system is 480V or some other voltage, the numbers would adjust accordingly.