thermorookie
Chemical
- Oct 25, 2013
- 4
Dear Forum,
i have a system with a pressurized air tank connected via a filter regulator (automatically adjusting throttling valve) to an air motor. Air is dry.
The concept is that when I open the valve, air passes from the air tank through the filter regulator which adjusts the outlet pressure to a certain level. The air motor will then be able to operate at constant pressure as long as the pressure in the tank is higher than the set point of the filter regulator.
Now my question is; what will happen to the temperature inside the tank, assuming that the heat capacity of the tank is negligible and the tank is isolated.
I know that over the filter regulator no external work is done , so w=o, and assuming adiabatic conditions -> h_in = h_out, and there will be a small temperature drop due to the Joules Thompson effect. Over the air motor, assuming an completely isentropic process the temperature will drop acc. to laws of isentropic expansion:
T2/T1 = (p2/p1)^(1-1/gamma),
gamma = cp/cv = 1.4 for air
However I am unsure how this affects the temperature of the remaining air in the tank. During the open valve period the tank pressure drops from p1 to p2, but what thermodynamic conditions govern?
Thanks
i have a system with a pressurized air tank connected via a filter regulator (automatically adjusting throttling valve) to an air motor. Air is dry.
The concept is that when I open the valve, air passes from the air tank through the filter regulator which adjusts the outlet pressure to a certain level. The air motor will then be able to operate at constant pressure as long as the pressure in the tank is higher than the set point of the filter regulator.
Now my question is; what will happen to the temperature inside the tank, assuming that the heat capacity of the tank is negligible and the tank is isolated.
I know that over the filter regulator no external work is done , so w=o, and assuming adiabatic conditions -> h_in = h_out, and there will be a small temperature drop due to the Joules Thompson effect. Over the air motor, assuming an completely isentropic process the temperature will drop acc. to laws of isentropic expansion:
T2/T1 = (p2/p1)^(1-1/gamma),
gamma = cp/cv = 1.4 for air
However I am unsure how this affects the temperature of the remaining air in the tank. During the open valve period the tank pressure drops from p1 to p2, but what thermodynamic conditions govern?
Thanks