tslewis
Structural
- Sep 18, 2003
- 29
For Design of Carbon Steel Tensin (non-upstand) rods to AISC I understand the following limits to be applicable:
1. Gross Yielding (Chapter D)
a) ASD
Ab - gross area of rod i.e. (pi*d^2)/4 where d is the nominal diameter of the rod
Nominal Strength Fn = Fy*Ab
FS - ASD Factor of safety = 1.67
ASD Allowable Strength = Fn/FS = 0.6*Fy*Ab
b) LRFD
As above but reduction factor phi = 0.9
LRFD Design Strength = phi*Fn = 0.9 *Fy*Ab
2. Threaded Part Chapter J3
a) ASD
Nominal Strength Fn = 0.75*Fu*Ab
FS - ASD Factor of safety = 2
ASD Allowable Strength = Fn/FS = 0.38*Fu*Ab
b) LRFD
As above but reduction factor phi = 0.75
LRFD Design Strength = phi*Fn = 0.563*Fu*Ab
My quesitons is, is can the Chapter D equaiton for fracture in the net section based on the actual thread area Ae be used in lieu of the eqution for the thread capacity from J3?
3. Fracture in the Net Section
a) ASD
Ae - threaded area
Nominal Strength Fn = Fu*Ae
FS - ASD Factor of safety = 2
ASD Allowable Strength = Fn/FS = 0.5*Fu*Ae
b) LRFD
As above but reduction factor phi = 0.75
LRFD Design Strength = phi*Fn = 0.75*Fu*Ae
I ask this as we get more capacity if we use the fracture equation above for a rod of known threaded area Ae vs that of the equation for a threaded part based on the gross area. Is it correct to assume that the fracture equaiton and the threaded part equationa are actually the same, except that the threaded part equation usses an assumption of teh treaded area Ae being equivelent to 0.75*Ab?
Thanks
1. Gross Yielding (Chapter D)
a) ASD
Ab - gross area of rod i.e. (pi*d^2)/4 where d is the nominal diameter of the rod
Nominal Strength Fn = Fy*Ab
FS - ASD Factor of safety = 1.67
ASD Allowable Strength = Fn/FS = 0.6*Fy*Ab
b) LRFD
As above but reduction factor phi = 0.9
LRFD Design Strength = phi*Fn = 0.9 *Fy*Ab
2. Threaded Part Chapter J3
a) ASD
Nominal Strength Fn = 0.75*Fu*Ab
FS - ASD Factor of safety = 2
ASD Allowable Strength = Fn/FS = 0.38*Fu*Ab
b) LRFD
As above but reduction factor phi = 0.75
LRFD Design Strength = phi*Fn = 0.563*Fu*Ab
My quesitons is, is can the Chapter D equaiton for fracture in the net section based on the actual thread area Ae be used in lieu of the eqution for the thread capacity from J3?
3. Fracture in the Net Section
a) ASD
Ae - threaded area
Nominal Strength Fn = Fu*Ae
FS - ASD Factor of safety = 2
ASD Allowable Strength = Fn/FS = 0.5*Fu*Ae
b) LRFD
As above but reduction factor phi = 0.75
LRFD Design Strength = phi*Fn = 0.75*Fu*Ae
I ask this as we get more capacity if we use the fracture equation above for a rod of known threaded area Ae vs that of the equation for a threaded part based on the gross area. Is it correct to assume that the fracture equaiton and the threaded part equationa are actually the same, except that the threaded part equation usses an assumption of teh treaded area Ae being equivelent to 0.75*Ab?
Thanks