You can find some discussion on flux monitoring at the CSI link that I provided above under "flux technology overview".
There is another paper on motor current monitoring at:
As I mentioned speed oscillation at FP would result in Fp sidebands around 1x in vibration spectrum. Here's my proof:
Let Wr be the radian frequency of the rotor (2*pi*1Xrunning speed) and Wp be the radian frequency associated with pole pass (2*pi*Fp). Assume we have torque oscillations causing speed oscillations so that position (angle) of rotor is given by theta(t) = cos(Wr*t+m*sin(Wp*t))
where m (known as modulation index in electrical circles) represents magnitude of frequency oscillation as a fraction of Wr. We can use trigonometry to rewrite it as theta(t)=cos(Wrt)*cos(msinWpt)-sin(Wrt)*sin(msinWpt). If m is small (<<1) then we approximate cos(msinWpt)~1 and we approximate sin(msinWpt)~msin(Wpt). Substituting into above equation for theta we get theta(t)~cos(Wrt)-msin(Wpt)sin(Wrt).
The term sin(Wpt)*sin(Wrt) is the amplitude-modulated form so well known in vibration circles, which gives rise to pole pass sidebands around rotor speed. Here's proof of that well-known fact:
sin(Wpt)*sin(Wrt) =½[cos(<Wr-Wp>*t)-cos(<Wr+Wp>*t) which has frequency components at Fp above and below running speed.
IF speed oscillation is really the source of the Fp sidebands around 1x, then we should be able to see oscillation of the shaft with a strobe. I have viewed the shaft with strobe in case where Fp sidebands were at least 10% of 1x running speed an saw no oscillations. In that case there was no broken rotor bars... presumably eccentricity. In any event it proves there are other ways for FP sidebands to show up... even though I don't understand them... don't see why amplitude modulation would come into play. Bottom line of all this rambling... can anyone explain why Fp sidebands around 1X are expected in the presense of broken rotor bar or eccentricity?