This value must be a scalar 2

[hoshang]

Hi,
Please find the attached image:

I'm not aware how this could be solved.
Any help would be highly appreciated.

 

[sticksandtriangles]

Is lamba pw a vector as well?

You may want to write a for loop to make this happen. Example from mathcad 15:

S&T -

http://www.re-tug.com

 

[hoshang]

Is lamba pw a vector as well?

Hi,
I'm sorry if I didn't provide whole data.
Please find the attached image:

 

[WinelandV]

So, you can't compare lambda _w directly to lambda_pw directly, because mathcad doesn't know which value in lambda_w (your vector) to lambda_pw (a scaler).

I imagine that line would work if you did the "vectorization" operator, as per your other thread. In the "Math" tab of the ribbon, click on "Operators" (has a cube root symbol on my version of mathcad), and at the bottom of the drop-down are the Vector and Matrix operators. The one you're looking for is a "V" with an arrow above it.

Make sure to highlight " lambda_w <= lambda_pw " and the apply the operator. Let us know if that fixes your problem.

 

[hoshang]

I imagine that line would work if you did the "vectorization" operator, as per your other thread. In the "Math" tab of the ribbon, click on "Operators" (has a cube root symbol on my version of mathcad), and at the bottom of the drop-down are the Vector and Matrix operators. The one you're looking for is a "V" with an arrow above it.

Make sure to highlight " lambda_w <= lambda_pw " and the apply the operator. Let us know if that fixes your problem.

Please find the attached image:

I'm sorry, but that doesn't fix the problem.
If you note the right side of the image, the comparison is OK. But when dealing with If statement, the problem comes.

 

[IRstuff]

If you stop and think about it, the example you show is actually a programmatic behavior embedded within the "=" functionality, but a program, as shown on the left side, does not use that functionality and must be explicitly programmed for it.

TTFN (ta ta for now)
I can do absolutely anything. I'm an expert!

https://www.youtube.com/watch?v=BKorP55Aqvg

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[WinelandV]

I don't use programming when I use mathcad, so LPS for IRstuff for filling in the missing knowledge.

 

[sticksandtriangles]

Hoshang,

I would make a for loop for your situation, compare lambda w to lambda pw in your for loop.

My example up above should be enough to make you dangerous.

S&T -

http://www.re-tug.com

 

[hoshang]

the example you show is actually a programmatic behavior embedded within the "=" functionality, but a program, as shown on the left side, does not use that functionality and must be explicitly programmed for it.

I tried several tricks but I couldn't catch this.
I removed the lower two If statements.
I tried with other comparison operators.
I tried also If and else statement instead of lower two If statements.
I tried If( , , , , , ) statement.
But with no success.
Any help will be highly appreciated.

 

[driftLimiter]

Just make a vector equal in length to the comparison vector that has the same value in each row.

 

[hoshang]

If you stop and think about it, the example you show is actually a programmatic behavior embedded within the "=" functionality, but a program, as shown on the left side, does not use that functionality and must be explicitly programmed for it.

Hi,
I know you have so many contribution in PTC Mathcad. So, I hope you be able to give a solution for this problem.

 

[structSU10]

try something like this:

 

[hoshang]

try something like this:

Accepted as solution. Highly appreciated.

 

[hoshang]

Hi,
This time I've stuck with this:

Any help would be highly appreciated.

 

[IRstuff]

I don't have any functional MC Prime, but I would imagine that if you used some sort of AND function for the two separate comparisons, that should work

TTFN (ta ta for now)
I can do absolutely anything. I'm an expert!

https://www.youtube.com/watch?v=BKorP55Aqvg

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[WinelandV]

If I'm reading the flow of your program correctly, aren't you checking the compact limit before you check the non-compact limit? If so, you don't need to check if lambda_f is greater than the compact limit. Try and remove the "lambda_pf <" from that line and see if it gets it moving.

 

[structSU10]

you use the i designation to define the function but none of the parameters have an i attributed to them. your lambda_rf should have an i and the i must be defined for the appropriate range.

 

[hoshang]

Hi, structSU10
Your help is highly appreciated and accepted as solution.
P.S., By accepted as solution, I mean I tried your approach and the problem is solved.

 

[hoshang]

Now another thought came into mind. Please find the attached image:

Is there any way combining these two steps into one step when calculating R_pc2 ?

 

[IRstuff]

That's what IF statements are for.

TTFN (ta ta for now)
I can do absolutely anything. I'm an expert!

https://www.youtube.com/watch?v=BKorP55Aqvg

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