gabvido
Mechanical
- Jun 25, 2009
- 1
Hi,
i have to calculate pressure thrust on 90° pipe bend (A106-B)with Caesar ii.(internal pressure P=250 kPa)
On double end there are anchors.
Caesar's results are more less than these obtained with manual method: R=2*p*A*sin(teta/2)
A=(3.14*d^2)/4 teta=90
bourdon effect: on
How can help me,please?
i have to calculate pressure thrust on 90° pipe bend (A106-B)with Caesar ii.(internal pressure P=250 kPa)
On double end there are anchors.
Caesar's results are more less than these obtained with manual method: R=2*p*A*sin(teta/2)
A=(3.14*d^2)/4 teta=90
bourdon effect: on
How can help me,please?