igorigor
Electrical
- Jan 9, 2020
- 6
Hello,
I have one differential relay and I'am trying to test transformer differential protection.
Using current injection test set I inject currents only from side of transformer.
For example, pick up value for differential protection is 500mA (secondary value):
- I inject in all three phases 500mA and I have a differential protection pick up. This is OK.
- If I inject in only one phase 750mA I get differential protection pick up. This is also OK.
(we have ''correction factor'' between 3 phase and 1 phase injection of 1.5, (500*1.5=750), and ok, I can find mathematical
explanation for this)
- for injection in two phases, we need to inject 565mA (500*1.13=565)
My question is, how to calculate this ''correction factor'' of 1.13 between 3 phase and 2 phase injection.
For example setting is for YNd11.
I hope you understand the question.
Thank you.
I have one differential relay and I'am trying to test transformer differential protection.
Using current injection test set I inject currents only from side of transformer.
For example, pick up value for differential protection is 500mA (secondary value):
- I inject in all three phases 500mA and I have a differential protection pick up. This is OK.
- If I inject in only one phase 750mA I get differential protection pick up. This is also OK.
(we have ''correction factor'' between 3 phase and 1 phase injection of 1.5, (500*1.5=750), and ok, I can find mathematical
explanation for this)
- for injection in two phases, we need to inject 565mA (500*1.13=565)
My question is, how to calculate this ''correction factor'' of 1.13 between 3 phase and 2 phase injection.
For example setting is for YNd11.
I hope you understand the question.
Thank you.