Tek-Tips is the largest IT community on the Internet today!

Members share and learn making Tek-Tips Forums the best source of peer-reviewed technical information on the Internet!

  • Congratulations MintJulep on being selected by the Eng-Tips community for having the most helpful posts in the forums last week. Way to Go!

UNITS

Status
Not open for further replies.

leo81

Bioengineer
Joined
Dec 6, 2007
Messages
43
Location
BE
Hi guys,

excuse me a stupid but important question about units:

if I want express all in N-Kg-mm

how have I to set the density value of 1g/(cm)^3?

Is it correct?:

F = 10 (10 N)
E = 0.010 (10 kPa)
density= 1E-6 (1 g/(cm)^3 = 1E-6 Kg/(mm)^3)

thanks,

Leo
 
I don't believe so. If you have Simuila's online support system, search for Answer ID 2579; there is a really nifty table which I found very convient to print out. Says if you want to use N and MPa units, you need to use tonnes instead of kilograms, so 1g/cm^3 would be 1e-9 tonnes/mm^3.
 
That Abaqus answer is in kg, meter, sec, so it's not really helpful because leo81 wants kg, millimeters, sec.

BUT, upon further inspection, I was only checking his density number, cause the question wasn't clear. But force should be in mN

Force = kg*mm/s^2 = 1 mN
Stress = kg/mm*s^2 = 1 kPa
Density = kg/mm^3

Therefore a density of 1 g/cm^3 = 1e-6 kg/mm^3, so you'd input 1e-6 into Abaqus.

If you instead used Mg (= 1e3 kg) as the mass, then you get a really nice system of units

Mass = Mg
Length = mm
Time = s
Force = Mg*mm/s^2 = 1 N
Stress = Mg/mm*s^2 = 1 MPa
Density = Mg/mm^3 = 1e12 kg/m^3

So a density of 1 g/cm^3 = 1e-9 Mg/mm^3, so you'd input 1e-9 into Abaqus
 
Status
Not open for further replies.

Part and Inventory Search

Sponsor

Back
Top