mk_27
Mechanical
- Jun 22, 2017
- 1
Hello every one,
I hope you are doing well. Currently i am a student and working as an intern in an industry. While working i encountered with an issue.
Issue - A liquid (e.g. water) cooling tank with capacity 30,000 liters is collapsed due to vacuum created by condensation when the washing process was carried out in tank. Hot water cycle with temperature 65° C causes the vapor in the tank and after the 30 second time gap, cold water cycle at 10° C was performed. This causes the condensation in tank. Pressure/ vacuum free Vent with Dia 104 were used initially. As it wasn’t sufficient to provide enough inbreathing, tank collapse.
So to solve this issue I did some calculations to find the diameter, can any one tell me that it is correct or not? I also referred API 2000 but i am not sure about it.
Calculation:
Volume of the tank (V1) : 30 m3
T1 – 65° C – 338 K
T2 – 10° C – 283 K
Time gap between hot and cold water cycle (t) – 30 seconds
:- V1/V2 = T2/T1 so V2 = 25.31 m3
∆V = V1 –V2 = 4.93 m3
Qair = ∆V / t = 600 m3/h
Now ,
𝑄 = (𝑉 𝐷²)/363.5 (V – velocity of air – 10 m/s )(assumed)
∴𝐷= √ (𝑄 ×363.5)/𝑣 = 147.42 mm
New D = 147.42 mm
Old D = 104 mm
thankyou.
I hope you are doing well. Currently i am a student and working as an intern in an industry. While working i encountered with an issue.
Issue - A liquid (e.g. water) cooling tank with capacity 30,000 liters is collapsed due to vacuum created by condensation when the washing process was carried out in tank. Hot water cycle with temperature 65° C causes the vapor in the tank and after the 30 second time gap, cold water cycle at 10° C was performed. This causes the condensation in tank. Pressure/ vacuum free Vent with Dia 104 were used initially. As it wasn’t sufficient to provide enough inbreathing, tank collapse.
So to solve this issue I did some calculations to find the diameter, can any one tell me that it is correct or not? I also referred API 2000 but i am not sure about it.
Calculation:
Volume of the tank (V1) : 30 m3
T1 – 65° C – 338 K
T2 – 10° C – 283 K
Time gap between hot and cold water cycle (t) – 30 seconds
:- V1/V2 = T2/T1 so V2 = 25.31 m3
∆V = V1 –V2 = 4.93 m3
Qair = ∆V / t = 600 m3/h
Now ,
𝑄 = (𝑉 𝐷²)/363.5 (V – velocity of air – 10 m/s )(assumed)
∴𝐷= √ (𝑄 ×363.5)/𝑣 = 147.42 mm
New D = 147.42 mm
Old D = 104 mm
thankyou.