amine errahal
Petroleum
- Jul 28, 2017
- 1
HELLO,
in order to do calculation basic on thickness calculation to separator. i do all the input in details (nozzles, manhole,saddle) i entered all the reinforcing of nozzles, the internal pression, temperature,allowable corrosion, diameter,thickness, the classes of flanges
but my problem is in the results (output):
i use a pressure of 6 bars but in calculation the pressure is defferent and with sign (-)
look here:
Required Thickness due to Internal Pressure [tr]:
= (P*Do*Kcor)/(2*S*E+2*P*(Kcor-0.1)) per Appendix 1-4 (c)
= (-16.801*1430.0000*0.994)/(2*-0.3E+07*1.00+2*-16.801*(0.994-0.1))
= -109.8021 + -84.0000 = -193.8021 mm
Max. Allowable Working Pressure at given Thickness, corroded [MAWP]:
= (2*S*E*t)/(Kcor*Do-2*t*(Kcor-0.1)) per Appendix 1-4 (c)
= (2*-0.3E+07*1.00*-224.0000)/(0.994*1430.0000-2*-224.0000*(0.99-0.1))
= -34.452 N/mm²
in order to do calculation basic on thickness calculation to separator. i do all the input in details (nozzles, manhole,saddle) i entered all the reinforcing of nozzles, the internal pression, temperature,allowable corrosion, diameter,thickness, the classes of flanges
but my problem is in the results (output):
i use a pressure of 6 bars but in calculation the pressure is defferent and with sign (-)
look here:
Required Thickness due to Internal Pressure [tr]:
= (P*Do*Kcor)/(2*S*E+2*P*(Kcor-0.1)) per Appendix 1-4 (c)
= (-16.801*1430.0000*0.994)/(2*-0.3E+07*1.00+2*-16.801*(0.994-0.1))
= -109.8021 + -84.0000 = -193.8021 mm
Max. Allowable Working Pressure at given Thickness, corroded [MAWP]:
= (2*S*E*t)/(Kcor*Do-2*t*(Kcor-0.1)) per Appendix 1-4 (c)
= (2*-0.3E+07*1.00*-224.0000)/(0.994*1430.0000-2*-224.0000*(0.99-0.1))
= -34.452 N/mm²