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voltage drop in acsr #2 calc 3

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maxPE

Nuclear
Feb 1, 2003
21
In discussions with the county engineer, he suggested that I could design my line myself and stamp it. P.E.ME ...as long as the calcs were reasonable. I may be over my head here but his big issue seemed to be the the voltage loss in ACSR 2 over a 9000 foot run at 4160 3 phase. The load is 26 kw. Intuitively it seems a no brainer to me since I have run #4 cu underground at 50 amps over 1500 feet with a marginally acceptable drop. The voltage drop at 4160 and 26kw seems to be minimal to me but he seemed to have difficulty with the significance. I cannot believe that surfing the net I cannot seem to locate a chart showing drop per amp-foot for ACSR #2 cable! I have used charts for standard copper before and they seem easy to locate. Any ideas? Am I missing something important as the county engineer implied?
 
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Comment: The voltage drop will somewhat depend on the ACSR #2 transmission line configuration.
Westinghouse Electrical Transmission and Distribution Reference Book includes for ACSR 2 in Table 2-A:
180A = Approximate current carrying capacity amps
1.41 = Resistance in Ohms per Conductor per Mile at 77degF Small Currents
1.69 = Resistance in Ohms per Conductor per Mile at 122degF
.592 = Inductive Reactance Ohms per Conductor per Mile at 1Ft spacing, Small Currents
.665 = Inductive Reactance Ohms per Conductor per Mile at 1Ft spacing, Current Approximately 75% capacity
0.1285 = Shunt Capacitive Reactance Megohms per Conductor per Mile at 1Ft spacing
 
To follow up on the previous post, the reactance spacing facotr must be added to the reactance at 1ft. The quoted reference includes a table of spacing factors.

3ft - 0.1333
4ft - 0.1682
5ft - 0.1953

Or the reactance can be calculated directly-

X = 0.004657 * f * log (Deq/Ds) ohms/mile

where
Deq is the GMD between condcutors
= cube root(Dab*Dbc*Dca) (ft)
Ds is the self-GMD
for seven strand cable = 0.4114 sqrt(A) * 12/1000
where A is the cross-sectional area in cm
 
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