111R
Electrical
- May 4, 2012
- 114
When determining the peak value of a voltage waveform, the oscillography from relays and waveform analyzers seems to always show the L-G voltage value as the "peak" value (peak of the sine wave). For a 345 kV system, the peak instantaneous value is given as 199 kV. The software also shows the RMS value as 199 kV divided by sqrt(2).
In reality, isn't the 199 kV an RMS value? The peak of the waveform, if actually plotted, would be 199 kV * sqrt(2)? For example, a wall receptacle in the U.S. is referred to as 120 V as read on an RMS meter, but we've all been in classes where the peak of the sine wave is shown as 169.7 V.
Based on the turns ratios of instrument transformers, the 199 kV makes sense as being an RMS value. But, why does the oscillography not plot the sine wave scaled correctly?
In reality, isn't the 199 kV an RMS value? The peak of the waveform, if actually plotted, would be 199 kV * sqrt(2)? For example, a wall receptacle in the U.S. is referred to as 120 V as read on an RMS meter, but we've all been in classes where the peak of the sine wave is shown as 169.7 V.
Based on the turns ratios of instrument transformers, the 199 kV makes sense as being an RMS value. But, why does the oscillography not plot the sine wave scaled correctly?