RiBeneke
Structural
- Nov 18, 1998
- 284
Hi. It has been so many months since I last participated here that I feel almost like a newcomer. I have been very overloaded with work lately.
I am designing small (maximum 5 metre high) steel mast structures for Australian conditions. The new Australian loading codes AS 1170 part 0 (general) and part 2 (wind) contain limit state factors that seem to give low wind forces. Can anyone tell me if I am interpreting them incorrectly, or do these codes, published June 2002, really give lower wind forces ?
The numbers are (AS 1170.2 section 2 etc)
Region A1 (non-cyclonic) with 3 sec gust wind speeds (50 year return period) Vr = 39 m/s.
Wind from any direction and structure with any orientation : Md = 1.00
Terrain category 2 and no nearby change of terrain category : Mz,cat = 0.91
No shielding : Ms = 1.00
No special topography (hill shapes or lee areas) Mt = 1.00
Then basic wind pressure p = 0.5 * 1.2 * (Vr * 0.91)^2 = 756 Pascal
to be multiplied by the appropriate pressure coefficients for the type of structure to give the wind force W.
For the ultimate limit state the overturning forces on the structure are calculated using factors
1.2 * G + Wu + 1.5 * Q (AS 1170.0 section 4 etc)
The puzzling part is that Wu is elsewhere confirmed = 1.00 * W (AS 1170.0 Commentary C4.2.2)
and therefore the ultimate limit state basic wind pressure is only 756 Pa.
This seems low by South African standards (which use Wu = 1.3 * W), but more importantly, it is also low in comparison with other calculations based on the older Australian codes of practice that were previously done for similar structures in similar locations.
Any ideas ? Thanks
I am designing small (maximum 5 metre high) steel mast structures for Australian conditions. The new Australian loading codes AS 1170 part 0 (general) and part 2 (wind) contain limit state factors that seem to give low wind forces. Can anyone tell me if I am interpreting them incorrectly, or do these codes, published June 2002, really give lower wind forces ?
The numbers are (AS 1170.2 section 2 etc)
Region A1 (non-cyclonic) with 3 sec gust wind speeds (50 year return period) Vr = 39 m/s.
Wind from any direction and structure with any orientation : Md = 1.00
Terrain category 2 and no nearby change of terrain category : Mz,cat = 0.91
No shielding : Ms = 1.00
No special topography (hill shapes or lee areas) Mt = 1.00
Then basic wind pressure p = 0.5 * 1.2 * (Vr * 0.91)^2 = 756 Pascal
to be multiplied by the appropriate pressure coefficients for the type of structure to give the wind force W.
For the ultimate limit state the overturning forces on the structure are calculated using factors
1.2 * G + Wu + 1.5 * Q (AS 1170.0 section 4 etc)
The puzzling part is that Wu is elsewhere confirmed = 1.00 * W (AS 1170.0 Commentary C4.2.2)
and therefore the ultimate limit state basic wind pressure is only 756 Pa.
This seems low by South African standards (which use Wu = 1.3 * W), but more importantly, it is also low in comparison with other calculations based on the older Australian codes of practice that were previously done for similar structures in similar locations.
Any ideas ? Thanks