Jerehmy
Structural
- Aug 23, 2013
- 415
Malone has a workshop slide show and a publication regarding wood diaphragm discontinuities links to which are posted below. I unfortunately don't have his book.
On slide 30 of the workshop, the transfer/sub diaphragm loading concept is shown. On slide 40, the collector force to transfer the transverse shear due to the discontinuity is shown.
If the transfer diaphragm chord is the same member as the collector, doesn't the transfer diaphragm chord force need to be added to the collector force?
So in his example, he has 6kip for the max collector force (slide 40). The transfer diaphragm chords have forces 5kip*15ft/20ft = 3.75kip (5kip is from slide 38). And this chord force occurs where the tension is maximum in the collector (point load on the transfer diaphragm). Don't these needed to be summed?
On slide 30 of the workshop, the transfer/sub diaphragm loading concept is shown. On slide 40, the collector force to transfer the transverse shear due to the discontinuity is shown.
If the transfer diaphragm chord is the same member as the collector, doesn't the transfer diaphragm chord force need to be added to the collector force?
So in his example, he has 6kip for the max collector force (slide 40). The transfer diaphragm chords have forces 5kip*15ft/20ft = 3.75kip (5kip is from slide 38). And this chord force occurs where the tension is maximum in the collector (point load on the transfer diaphragm). Don't these needed to be summed?
