Yield Strength of Pipe

[_Yoda_]

I have a 1" NPS x 70" Schedule 80 steel pipe vertically cemented in the ground. A force is applied at the top of the pipe at a 45 degree angle downward.
A deformation happened at the very bottom of the pipe, the cement did not fail. The pipe failed from one side in tension and the other in compression.

Question: How can I find the yield strength of the pipe? Using that information I will find the minimum amount of rotational force that had to be applied to cause the pipe to fail.

Am I looking at this problem the correct way?
Any help and advice will be greatly appreciated. Thank you.

 

[rb1957]

"rotational force" ? do you mean moment ? be aware that the inclined force is making compression stresses higher and tension stresses lower. Sure you may be able to quickly show that the axial stress (due to the axial component of the load) is small compared to the bending stress … it's a matter of precision and understanding the problem.

I suspect that the failure started with a compression yield/buckle which induced a tension yield/failure?

another day in paradise, or is paradise one day closer ?

 

[MintJulep]

https://mechanicalc.com/reference/beam-analysis

You have a cantilever beam.

 

[EdStainless]

Please don't double post

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P.E. Metallurgy, consulting work welcomed

 

[oldestguy]

See my comments in your other double posting, which by the way is not good use of this system.

 

[chicopee]

Theoretically you calculate the bending stress and the compressive stress at the bottom of the pipe? Summing those two type of stresses at its anchoring point should have values lower than the yield stress. From a practical standpoint, I would calculate these stresses with a safety factor. Yield stress of materials are listed in engineering handbooks, text books and on line.