Anchor Bolt Tension in Circular Pattern (For Vessels) 1

For a thin cylindrical beam, bending stress is equal to Mc/I +/- P/A.
Set c = R, I is pi*R^3*t, and A is 2*pi*R*t, where t is the thickness, R is the radius.
Then stress is equal to M/(pi*R^2*t) +/- P/A.
This is a varying stress, but the equivalent axial load that would give that same stress is A*stress or
(M/(pi*R^2*t) +/- P/A) * 2pi*R*t = 2M/R +/- P
And, assuming this total force is divided amongst N bolt, the load per bolt is 2M/(RN) +/- P/N or 4M/(ND) +/- P/N

There may be more elegant ways to show that, but it's still based on the Mc/I +/- P/A.

People have tried to complicate this by considering the composite steel/concrete area in the foundation. However, the stress in the cylindrical shell is assumed to be of this load distribution, so there's not much motivation to assume a different load distribution above the concrete surface than below.

Thanks for your fast response. Your answer did enlighten me.