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Calculating displacement and clamping force

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Driekes

Mechanical
Jul 7, 2016
4
Hi guys,

I`ve been stuck at this for days, maybe time to get some other opinions.

I work in the pipe closure industry and for a next project we need a bigger clip to secure our bevelprotectors (ring). A bevelprotecor is something that is placed inside a pipe, where a plug has been installed, and has the purpose of securing the plug in the pipe.

Some pictures to give a better understanding (plug not drawn):
Capture4_itqih2.png

Capture3_g3gh9l.png


This clip will be inserted between the 2 lips of the bevelprotector. When the clip is flattened, it pushes the protector outwards to clamp against the inside of the pipe


Capture1_l8fubq.png


I want to find out what happens when a total force of 18kN is placed on the arcs of the clip.
When will the point where the two arcs meet in the middle, meet the bevelprotector and how much force is necessairy for this.
Is this possible when there only is a backlash of 1mm? what will happen to the clip when a force of 18kN is applied?

Both the clip and the bevelprotector are made from steel DD11 (1.0332).

If anyone could help me get started, I would really appriciate it !
And ofcourse pay it forward ;)
 
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