Recent content by AliGrailly

i used the formula of B31.3 for 1/6 thickness and internal pressure but data sheet is different i do not why used max pressure 226 psi for 1" and thk=0.133 max allowable stress in table A1=20ksi amd table A1-M=138 or 137.9mpa following used for which code ? p=2s×e×t / ((D-2×y×t)×sf) sf between...

hi i used eq : p=2se(t-c)/d-2×y(t-c) to calc max pressure for A106-B seamless at temp 100F Od=1.315 , t=0.133"-12.5% s=137.9mpa Result=26.3mpa or 263bar but i visited some websites and got following formula with safety factor ( while b31.3 not mentioned safety factor just states basic...

From Code B31.3

FootNote Table 323.3.5 : 👉 (2) Energy values in this Table are for standard size specimens. For subsize specimens, these values shall be multiplied by the ratio of the actual specimen width to that of a full-size specimen, 10 mm (0.394 in.).

please help me to understand note2 Note 2 : (min energy for subsize) = it says min energy for standard_size depend on tensile × subsize_width/Full_size(10) if min energy for full size = 18 j and obtainable size be 5 mm so 18× (5/10) =18×0.5=9 j ???

So , i could not find right value

Why cannot use Code UG-28(f) for vessel under external pressure greater than 15 psi ? it is depend on temperature Or material impacy testing ... another question is there temp l8mitation for 15psi and where can i find it in Asme section viii ?

is Factor B in 750 F or 400 C degree 2750psi or 2903 psi ... i am afraid of wrong calculation manual

WITH D/T=69.7 , L/D 50 in tabular values figur G section ii 60 80 0.306 0.172 Factor A General interpolation =0.24101-03 Factor A with exp(use ln in linear interpolation ) = 0.2267-03 Now which ones to be used ?

i found following from searching here : Example for first row (natural logs): Do/T = 500, (log=6.2146), L/Do = 0.231 (log=-1.46534): log(A) = -0.4385-(-1.46534+1.60944)/(-0.91629+1.60944)*(-0.4385+1.19733) = -0.59625 This would give (excluding the factor 10^-3) A=exp(-0.59625)=0.551 , quite...

hi linear 0.23 or 0.24 ? and if log-log interpolate be accurate so what is the final result ? in somewhere i saw cal for 69.7 & 50 >>> 0.25-03

Hi i could not extract factor A from tabluar values figure G Material from table HA-1 D/T=69.7 L/D=50 1-A=? 2- if there is not same D/L according to L/D how shall be do , forexample in above there are 50 in L/D 60 and also 80 Ex: D/t=20 , L/D=40 A=0.275-02 D/t=22 , L/D=40 Whats A ...

So , this can be an example for all are looking for.

hi how can i find total bolt load for wn flange 12" Class 600 Also G , Hg and b gasket spiral wound thanks for helping