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Note 2 Table 323.3.5 min impact energy

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AliGrailly

Mechanical
Dec 8, 2020
72
please help me to understand note2

Note 2 : (min energy for subsize) = it says min energy for standard_size depend on tensile × subsize_width/Full_size(10)

if min energy for full size = 18 j and obtainable size be 5 mm so 18× (5/10) =18×0.5=9 j ???



 
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FootNote Table 323.3.5 :
👉 (2) Energy values in this Table are for standard size specimens. For subsize specimens, these values shall be multiplied by the ratio of the
actual specimen width to that of a full-size specimen, 10 mm (0.394 in.).
 
Table 323.3.5 in WHAT???
What type of specimens???
What type of impact???
 
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