Greg,
Originally the post was to understand how to calculate the frequency of the engine. Just to make sure I understand your first post:
Engine running at a constant 1500 RPM (4 stroke, 4 cylinder), would have a dominant frequency of 50 Hz and another at 25 Hz (not considering # of ignition)...
Here's the full image, the 1.5 Hz seems to have harmonics as there are multiples (3.7, 6.4, 12.58 Hz...), as you've said, it could be the body natural frequency. There are some published articles about suspension for vehicles being around 1-2 Hz. I think it might be the case for this box truck...
Hi,
I have a 26' box truck from Hinos (Chinese diesel truck). I placed a couple accelerometers on the box to see what frequencies are present. Several low frequencies crop up (1.5, 3.7, 14.7, 35.0 Hz). To calculate the dominant frequency of the diesel engine it would be:
RPM/60 = Hz
Then the...
I'll put some accelerometer this week to get a realistic idea of what the vibrations range from a commercial truck. But yes, I need to minimize the vertical vibration as much as possible as I have sensors that are very sensitive to the vertical motion.
Thank you guys for the links, I am...
Thank you, Greg. The Bose system sounds like it could be a candidate although it looks like they sold their technology to ClearMotion and ClearMotion is still in R&D phase.
Hi All,
I am mounting a rectangular structure(115 lb)on the underbody of a commercial truck and need to isolate the vibrations being transferred from the truck while driving; The truck produces a low random vibration (1-15 Hz). I have been exploring options such as visco-elastic rubbers, and...
I am working on a research project that involves mounting a 5x6x0.375x120" beam to the side of a 18-wheeler. I have done a modal analysis to get an idea of the natural frequencies, I am looking into using MSC Adams in the future. Until then, I was planing on doing a stationary free-free mount...
Hello all,
I am trying to figure out a way to have Excel output possible gear ratio combinations of a limited set of gears.
The calculation would consist of number of teeth (N1) divided by number of teeth of another gear (N2) such that N1/N2 = Ratio1 while other iterations would add more...
