DrZoidberWoop gave brilliant explanation.
KootK (as always) was clear and convincing.
Call my anxiety persistence, but after some
digging, I have came upon some bridge
gusset plates and hot-rolled, open I sections.
To my humble understanding, pictures (to
some degree) represent the idea of...
Adding transverse stiffeners perpendicular to a web
(I beams and columns) stiffen the web against out
of plane deformations. What about adding only
transverse stiffeners parallel to the web? It’s a one
storey project involving 6м span, RC columns, simple
steel king post roof truss (not tied king...
Single girder Mмax=101kN.м
Single girder load 20/2=10kN.м
HEA220
CTICM-LTBeam-Mмax(cr)=132kN.м- Fine!
IPE300
CTICM-LTBeam-Mмax(cr)=61kN.м- Rejected.
To recap,
In this particular case the two HEA girders have enough potential to handle LTB even without diaphragms i.e. acting as a typical...
I’m not quite confident, that timber joists have enough bracing potential to restrain steel girders.
To simplify it a bit:
Girder Span= 9м
Load [LL+DL]= 20kN/m
1.First variant- Single girder- HEA360; weight=112kg/m.
2..Second variant- Twin girder with diaphragms (where the unbraced length...
It’s a simple house project, where the single I-beam in the middle of a spacious living room, became too high(deep), L= 30 feet. The investors insisted on reducing the I-beam size.
So I decided to use two I-beams with diaphragms every 3-4 feet, (because there was a „pressure“ to use as little...
Can I assume (from the picture) that the unbraced length equals the distance between diaphragms?https://files.engineering.com/getfile.aspx?folder=ea114c13-88a5-4491-8e6a-62e8c9b8ff0c&file=1.jpeg
It’s a small flitch beam from a porch. 1..The timber beam is rectangular; height to width ratio 2:1; 6x3(75x150mm) 2..U-sections are facing each other on both sides of the timber beam, with their closed lateral sides; 3..Bolts are placed at the flanges as near as possible. 4..I can tie upper...
A timber beam sandwiched between two cold formed U-sections, all bolted together. Can I assume, that the U-sections are restrained against lateral torsional buckling?
Thank you, jayrod12
The length of horizontal projection of a slanted beam is always shorter than the actual length along the incline. Hence, multiplying the latter with cosine, just equals loads.
Thank you, BAretired
If the upper connection of the slanted beam is pinned, than there is tension...
Imagine a roof’s sloped beam, similar to a rafter. The roof has a 25 degree pitch angle. The live load is uniform and with downward vertical direction, causing bending in the beam. Is it correct (possible), to reduce the loads [DL and LL], multiplying them by 0.90(cosine 25 degrees) in order to...
