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The Wiki article mentions line losses in a transmission line. Losses in watts = I² x R. For a fixed length of line the resistance R is fixed. For a fixed resistance, the heat losses dissipated is = V² x R. Therefore is you are using selected conductor size and a given acceptable loss, the...

Check here...

hisham It sounds like you are caught up in that old example the flow of electrical current is like water flowing through a hose. Nothing could be further from the truth. If you take a simple circuit like a lamp and connect the two wires from the lamp to 120 volts the lamp lights. At the time...

You obviously have other paths being used. Does you local code allow the water pipes to be used in the grounding system? 100 amps is a lot on a single phase line. I am surprised that you are not receiving electrical shocking complaints.

check this information first http://findarticles.com/p/articles/mi_m0BPR/is_10_22/ai_n15766075/?tag=content;col1

I agree with both of the previous posts. The owner of the line will have requirements that you must follow. Did you have a distance in mind?

Could you give an example of a through power flow ?

Quote waross "So when a motor is operated at the star voltage rather than the delta voltage the life expectancy is 1/700 or 0.14%." I don't follow your math.. I would say the operation at the voltage stated would reduce the life time hours = 700/expected lifetime hrs. I am not familiar with...

%Z is not the transformer impedance but you can obtain it form the transformer information. The links below explain it in detail. www.jcmiras.net/jcm/item/117 www.jcmiras.net/jcm/item/116

I would not think a water hose clamp would be listed for this purpose. Why not use a nylon strap?

Have you calculated the amperage at 66 kv and 220 kv. Looks like you need a generation plant in the back yard. At 220 kv calculate the VD at max load. Then decide what you need to do.

Are you speaking commercial/industrial design or something like utility power distribution? They are different. I google your question and found the following: http://www.google.com/search...

Good answer Bill. You slapped the MBA and made it seem like kiss. I can't believe there is much difference in cost for either A or B.

Stanley I would get my voltmeter and measure all of the voltages for myself. Scotty has one possibility, but these reading are crazy.

This may help http://www.summit.com/industries/marine/downloads/marine-cable-brading-and-cutting/Drilmar/Drilmar_SCPDC_TypeP600.pdf

Thanks Bill.

I have 2 15 kva loads connected to a 3 phase Y generator 220 phase to phase voltage. Load connected A-B and A-C. The load current is 15 kva/(0.22 kva 1.73 = 39 amps. If the load was connected Phase to neutral the neutral current would be 39 x 1.73 = 64 amps. However in this case the load is...

Utilities I know would just put the Regs on non auto or manual and transfer. There was no attempt to adjust the voltage, but the subs were far apart. Yours may be close together may need to consider that.

I assume these conduits are underground. Since you only need to supply 722 amps, you can use either 3 4/0 15 kv 90C @ 285 amps or 3 3/0 15 kv 90C @ 250 amps using detail 2 & 3 conduits per Table 310-60. 2 500 15 kv is not quite large enough.

This application would apply to a y-d or a d-d hook up rather than the one you have. Maybe your client thinks they know more that you.