Yes i did it already for 78 blades. i did it one by one. The last blade is out per .4 degrees because of the stack up in the last digits. But i would like to find out a relation for example. Do i have to use memb_i = 4.615 + 0.5sin(idx1) where idx1 will be the angle. i don't know. I am lost...
Hi to everyone,
I there is someone that can help me. I have an impeller with 78 blades and i want to make the angle variable. if you pattern the blade you will have 360/78 you have 4.61535 each angle of blade. No i want to make this gap to vary with a total amplitude 1 degree. Like the...
