drawoh,
moon161,
The test piece will have a flange on one end that will be attached to a u-joint. I see the u-joint as a pivot point to simplify calculations. We will be applying the 20 Ton force in the middle of a 12' shaft, we want to test for catastrophic failure. The test piece will rotate...
I spoke with my supervisor to get some clarity. He changed gears and would like me to calculate the momentum when the shaft reaches 90 degrees, then research some wire rope/slings to find some elasticity values. With the values I can find the stopping distance and hopefully the shock load that...
hydtools,
I had used the impulse/momentum to assume 1ms of stopping time in that equation. That is how i got the 40000lb impulsive force back. My boss is back today so I will grill him with some questions.
Drawoh,
I was given that number by my supervisor, it doesn't seem correct. I can't imagine the shaft would survive rotating that fast to a stop. Ill talk to my boss tomorrow and see what he has to say.
Thanks for helping
Drawoh,
I am visualizing this in failure after the shaft breaks. The force is not continuous, the force will only be applied for calculation purposes, 1ms.
Thanks
Okay, I've linked a picture I quickly sketched.
The distance in the torque equation was the distance(6feet) that the force was applied, from the pivot point. What if instead of saying stopping distance for the sling or elastic forces, I said the end of the shaft hit a wall and stopped. Could...
Hello everyone,
I have a problem that I was asked. The company that I work for is building a fatigue testing machine, they asked me to calculate a component of said machine. The part I am calculating is the safety leash/lasso that would keep the shaft from destroying the machine in the event...
