Hi,
It's not clear to me from the NEC's definition how voltage drop should be calculated in this case (see diagram).
I can find the drop across the cables serving the 2 loads (branch circuits) using the usual 2*I*R formula for each circuit and dividing by 120 for the first load and by 240 for...
Thanks for everyone's input so far. A few comments from what I've gathered:
So it seems that solution A) would be the correct calculation according to this argument. It makes sense to me because the argument is saying something like: "the transformer is providing 480v, 5.4v are being dropped...
Correct, I made the assumption that these are ideal transformers. The loads are fairly light and composed of electronic devices mostly (cameras, radar detectors, and network switches) so I'm thinking that droop may not be an issue and therefore can be left out of the calculation.
Thanks for the input so far.
It seems that the Canadian code makes it clear, and according to the Canadian code it seems that the correct calculation would be B) since the voltage in the denominator of the voltage drop % is the voltage at the point of utilization.
However, it seems that for the...
Hi,
I have a question about how voltage drop %, per the National Electrical Code (NEC), should be calculated for the attached circuit. Would A or B be the correct calculation? My main doubt is if the voltage drop due to the feeder cable should be divided by the voltage of the secondary side of...
