lalver1
Electrical
- Apr 8, 2020
- 5
Hi,
I have a question about how voltage drop %, per the National Electrical Code (NEC), should be calculated for the attached circuit. Would A or B be the correct calculation? My main doubt is if the voltage drop due to the feeder cable should be divided by the voltage of the secondary side of the transformer (480v) or if it should be divided by the voltage of the utility source voltage (240v). I'm not clear which one of the two the NEC considers the 'source' voltage.
A) [ul]
[li]Feeder % voltage drop = 5.4v / 480v = 1.13%[/li]
[li]Branch % voltage drop = 0.4v / 120v = 0.33%[/li]
[li]Total % voltage drop = 1.13% + 0.33% = 1.46%[/li]
[/ul]
B)[ul]
[li]Feeder % voltage drop = 5.4v / 240v = 2.25%[/li]
[li]Branch % voltage drop = 0.4v / 120v = 0.33%[/li]
[li]Total % voltage drop = 2.25% + 0.33% = 2.58%[/li]
[/ul]
Thanks for your help!
I have a question about how voltage drop %, per the National Electrical Code (NEC), should be calculated for the attached circuit. Would A or B be the correct calculation? My main doubt is if the voltage drop due to the feeder cable should be divided by the voltage of the secondary side of the transformer (480v) or if it should be divided by the voltage of the utility source voltage (240v). I'm not clear which one of the two the NEC considers the 'source' voltage.
A) [ul]
[li]Feeder % voltage drop = 5.4v / 480v = 1.13%[/li]
[li]Branch % voltage drop = 0.4v / 120v = 0.33%[/li]
[li]Total % voltage drop = 1.13% + 0.33% = 1.46%[/li]
[/ul]
B)[ul]
[li]Feeder % voltage drop = 5.4v / 240v = 2.25%[/li]
[li]Branch % voltage drop = 0.4v / 120v = 0.33%[/li]
[li]Total % voltage drop = 2.25% + 0.33% = 2.58%[/li]
[/ul]
Thanks for your help!