Certainly simple. For those who are wondering wondering where As ≅ Mu/4d comes from . . . using our well know equation ⇒ Mu ≤ 0.9Asfy(d-a/2).
Providing Mu in k-ft units, assuming the term (d-a/2) is equal to 8/9*d, rearranging the terms to As=Mu/[(0.9fy*8d/9)/12] and using a steel yield of...
The file is a pdf stored in Eng Tips. It's the algebraic derivation for the equations above from the equation Mn = Asfy(d-a/2). Without the derivation (not choosing to down load the file) it's simple enough to verify the given equation is an exact solution of As by taking the result, As (exact...
thread507-215879
Known: Mu (in kips), b (in), d (in), f'c (ksi) and fy (ksi).
Cu = β1*f'c*b*d/fy
(Remember: β1 is the depth factor for an equivalent compression stress block)
Equation 1a:
Required Steel Area (exact solution), As = Cu(1-(1-2Mu/Øfy d Cu)0.5)
Ø = 0.9 with the assumption the beam...
Chapter 5 in the "PCI Design Handbook" (for Precast and Prestressed Concrete) may be of some help. The chapter discusses product handling with information on handling considerations. Included are a couple of diagrams for locating pickpoints for rectangular panels and provides a few...
