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what about using a single phase current relay to just switch a 120VAC light across the power rail as needed? Omron K8AB-AS2 comes to mind. Hard to tell without any actual indication of failure mode or even typical current curve for normal operating conditions. Undercurrent / Overcurrent should...

not sure about generators but for transformers its in the order of some pico coulombs, I'd be alarmed if it was nano coulombs.

Well you've certainly posted this topic far and wide across multiple sites... You will need a physical interlock system. You will need a commissioning plan + signoff. You will need some sort of regular safety checklist which checks that the interlock is still functioing correctly. To be safe...

I would go back to the manufacturer. The reactance is measured at rated voltage, if you arent running it at rated voltage then you won't get the rated MVAr. Also a good idea to check the rating plate vs the type test certificate, they may have made an error in authoring the cert. Or you are...

No, you are purely testing the insulation of the winding to earth. If you earth the neutral terminal during SS you would be testing zero sequence impedance (and drawing a lot of amps!). Just be sure to check the rating plate for the insulation level. Some terminals which are designed to be...

33kV to 433/415V is pretty standard for a distribution transformer in Australia. The 33k/433 will likely also be cheaper, smaller and more efficient than the 4.16k/433 as the HV current is a lot lower on the 33kV. No experience with the cost of cabling for the 500m at the different voltages...

may another solution be to use a motor-generator set to do both the voltage and frequency conversion and drive the whole line at it's european supply frequency and voltage?

As jghrist said the Load Loss is proportional to the square of the current. No-Load losses are there all the time. The figure quoted for load loss at 85 degrees is at rated current, so if you know what current you are drawing, it's a mater of (Measured_I / Rated_I)^2 * 58055 + 12760 It won't be...

Can you come up with a function that takes alpha and beta as inputs and gives you 'sensitivity to small movements' as an output?

Get MS Visual C# 2010 Express (free) and try out WPF Animation on a Windows Form application. Plenty of tutorials out there to get some simple animation happening and C# should be simple to pick up if you've used C++ and Java before. Or, as gsal mentioned, Phython would be good fit for this...