Dec 4, 2014 #1 ELJ51 Mechanical Mar 11, 2014 4 0 0 US Does anybody know how to find or calculate the specific heat capacity of 50% Methanol 50% Water mixture? I have a chiller running at -40°F and I need the thermodynamic properties to calculate the load. Thanks
Does anybody know how to find or calculate the specific heat capacity of 50% Methanol 50% Water mixture? I have a chiller running at -40°F and I need the thermodynamic properties to calculate the load. Thanks
Dec 5, 2014 #2 willard3 Mechanical Jan 14, 2006 1,437 0 0 US Marks Handbook for Mechanical Engineers. Upvote 0 Downvote
Dec 5, 2014 2 #3 chicopee Mechanical Feb 15, 2003 6,198 0 36 US I think that the formula is: (Cp)mixt= ((Cp*M)methanol+(Cp*M)water)/ (Mmethanaol+Mwater); M stands for mass. Upvote 0 Downvote
I think that the formula is: (Cp)mixt= ((Cp*M)methanol+(Cp*M)water)/ (Mmethanaol+Mwater); M stands for mass.
Dec 6, 2014 Thread starter #4 ELJ51 Mechanical Mar 11, 2014 4 0 0 US Much appreciated! Thanks! Upvote 0 Downvote
Dec 7, 2014 #5 Compositepro Chemical Oct 22, 2003 7,721 0 36 US Simple rule of mixtures may not be terribly accurate for a non-ideal mixture. Upvote 0 Downvote
Dec 7, 2014 #6 GHartmann Chemical Nov 15, 2011 246 0 0 US Try to do a web search for this data...often data like this is already published Upvote 0 Downvote