coloradobridges
Civil/Environmental
- Aug 13, 2004
- 23
AASHTO Figure 5.6.2A (in the 17th ed. standard spec) shows a simplified pressure distribution for wall elements embedded in rock. The formula for the passive resistance of the rock is given as:
Pp = s*D /(1+tan B)/(D+2^.5*b)
If s is shear strength of rock in psf, shouldn't the (D+2^.5*b) term be in the numerator to make the units work (i.e. give Pp in lbs or kips)?
Thanks in advance.
Pp = s*D /(1+tan B)/(D+2^.5*b)
If s is shear strength of rock in psf, shouldn't the (D+2^.5*b) term be in the numerator to make the units work (i.e. give Pp in lbs or kips)?
Thanks in advance.