man_of_steel
Structural
- Feb 16, 2024
- 3
Hey guys, I'm currently working on a bridge load rating using Standard Specs (17th Ed.) LFD methodology. Need to provide axial-force rating factors for steel cross-frames and lateral bracing members, most of which are either T or single-angle sections. But Std. Specs don't really offer much guidance for computing the compressive resistance of singly-symmetric or unsymmetric sections... Does anyone have experience with this calc?
The basic LFD compressive resistance calc (eq 10-150) is straightforward and easy - too easy, it felt like, considering that modern LRFD has a whole bunch of additional checks for (flexural-)torsional buckling (FTB) failure modes depending on your cross-section, including specific provisions for single-angle members. But all the Std. Specs say about it in Section 10.54.1.1 is a footnote at the bottom of the page that just reads: "Singly symmetric and unsymmetric compression members, such as angles or tees... 'may' also require consideration of flexural-torsional or torsional buckling. Refer to the Manual for Steel Construction, Ninth Edition, 1989, AISC." (Not even referencing a specific chapter? Could they have been more vague? lol)
So then I'm going through the 9th Steel Manual (which is entirely based in ASD, not LFD) trying to track down info on FTB. Chapter E gives a general equation for allowable compressive stress F[sub]a[/sub], then the associated commentary provides an additional clause for considering (F)TB. That section has you compute an effective KL/r for singly-/un-symmetric sections, which you substitute in for regular KL/r in the F[sub]a[/sub] equation from before. So I went through all that, but then... what do I do with F[sub]a[/sub]? Do I plug it back into LFD eq. 10-150 in place of F[sub]cr[/sub]? If so, do I keep the 0.85 factor in front of the F[sub]cr[/sub]A term? Subbing an ASD allowable stress into an LFD equation feels incompatible - and in fact, if I do just plug in the substitution, the compression capacity gets cut almost in half... For comparison: I also have to provide LRFD ratings, and the LRFD capacity for all the tee and angle members is much more in line with the LFD capacity as calculated by the original equation (P = 0.85F[sub]a[/sub]A).
So what am I doing wrong? How am I meant to use that F[sub]a[/sub] value from AISC? Am I missing something here? Or do I not even bother, and just ignore (F)TB effects and stick with the basic eq. 10-150 for all sections?
The basic LFD compressive resistance calc (eq 10-150) is straightforward and easy - too easy, it felt like, considering that modern LRFD has a whole bunch of additional checks for (flexural-)torsional buckling (FTB) failure modes depending on your cross-section, including specific provisions for single-angle members. But all the Std. Specs say about it in Section 10.54.1.1 is a footnote at the bottom of the page that just reads: "Singly symmetric and unsymmetric compression members, such as angles or tees... 'may' also require consideration of flexural-torsional or torsional buckling. Refer to the Manual for Steel Construction, Ninth Edition, 1989, AISC." (Not even referencing a specific chapter? Could they have been more vague? lol)
So then I'm going through the 9th Steel Manual (which is entirely based in ASD, not LFD) trying to track down info on FTB. Chapter E gives a general equation for allowable compressive stress F[sub]a[/sub], then the associated commentary provides an additional clause for considering (F)TB. That section has you compute an effective KL/r for singly-/un-symmetric sections, which you substitute in for regular KL/r in the F[sub]a[/sub] equation from before. So I went through all that, but then... what do I do with F[sub]a[/sub]? Do I plug it back into LFD eq. 10-150 in place of F[sub]cr[/sub]? If so, do I keep the 0.85 factor in front of the F[sub]cr[/sub]A term? Subbing an ASD allowable stress into an LFD equation feels incompatible - and in fact, if I do just plug in the substitution, the compression capacity gets cut almost in half... For comparison: I also have to provide LRFD ratings, and the LRFD capacity for all the tee and angle members is much more in line with the LFD capacity as calculated by the original equation (P = 0.85F[sub]a[/sub]A).
So what am I doing wrong? How am I meant to use that F[sub]a[/sub] value from AISC? Am I missing something here? Or do I not even bother, and just ignore (F)TB effects and stick with the basic eq. 10-150 for all sections?