Adding an Inch symbol (") into a string expression 2

[ChaseWichert]

Okay, so I am working with expressions, and have a need to type in 4.25" into a string expression, but it thinks that the " is part of the string statement and gives me an unmatched error. I have also tried to insert it as a char( " ), but I don't even know if that is correct as I have not been able to successfully use it.

Thanks!

 

[cowski]

Change the expression to read:

"4.25" + char(34)

 

[JohnRBaker]

OK, try using...

"4.25"+CHAR( 34 )+" TYPE 50 PIN"

...as the value of your Expression.

John R. Baker, P.E.
Product 'Evangelist'
Product Engineering Software
Siemens PLM Software Inc.
Industry Sector
Cypress, CA

http://www.siemens.com/plm

UG/NX Museum:

http://www.plmworld.org/p/cm/ld/fid=209

To an Engineer, the glass is twice as big as it needs to be.

 

[ChaseWichert]

Okay, I figured char( " ) that nx gave me when I used the formula thing wasn't correct. And I was also trying to use & instead of +
Thanks!