It would be best to do a titration to determine total alkalinity, but a neutralization calculation based upon pH is quite simple:
For pH 12, [OH-] = 10-2 = 0.01 moles/L
Hence, neutralization will require [H+] = 10-2 = 0.01 moles/L:
OH- + H+ = H2O
As the source for H+, can use technical grade hydrochloric acid (37 wt%, SG 1.19).
Since HCl has FW of 36.46, the hydrochloric acid contains [HCl] = [H+] = 12 moles/L.
Hence, to supply 0.01 mole H+ requires 0.01/12 = 0.000833 L of hydrochloric acid.
To neutralize 1 m3 of alkaline solution would require 0.833 L of hydrochloric acid of this concentration. In order to greatly reduce the HCl(g) pressure, I would use hydrochloric acid of lower concentration, e.g., 30 wt%, if available. For 30 wt% HCl, 1.03 L would be required for neutralization of 1 m3 of alkaline solution.