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Analytical rigid surface revolve feature failed in Abaqus Scripting

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VictorAntona

Industrial
Joined
Feb 1, 2014
Messages
6
Location
ES
Hi, I'm using Abaqus Scripting to make an impact model in my final degree proyect.

This is the first time working with Python and I'm having some problems.

I have to design a cylinder with the next features (3D and analytical rigid surface)and when I run the script in Abaqus I always receive this message "Analytical rigid surface revolve feature failed"

This is my code, and any help will well appreciated. Thank you.


from abaqus import *
from abaqusConstants import *
import regionToolset

session.viewports['Viewport: 1'].setValues(displayedObject=None)

#----------------------------------------------------------------------

#Create model

mdb.models.changeKey(fromName='Impact', toName='Impact')
shellModel = mdb.models['Impact']

#-----------------------------------------------------------------------

#Create the shell

import sketch
import part

shellProfileSketch = shellModel.ConstrainedSketch(name='Shell CS Profile',sheetSize=5)
shellProfileSketch.rectangle(point1=(0,0), point2=(0.1,0.1))
shellPart=shellModel.Part(name='Placa',dimensionality=THREE_D, type=DEFORMABLE_BODY)
shellPart.BaseSolidExtrude(sketch=shellProfileSketch, depth=0.004)

#Create proyectil

import sketch
import part

proyectilProfileSketch = shellModel.ConstrainedSketch(name='Proyectil CS Profile',sheetSize=5)
proyectilProfileSketch.Line(point1=(0,0), point2=(0.0065,0))
proyectilProfileSketch.Line(point1=(0.0065,0), point2=(0.0065,0.025))
proyectilProfileSketch.Line(point1=(0.0065,0.025), point2=(0,0.025))
proyectilProfileSketch.Line(point1=(0,0.025), point2=(0,0))

proyectilPart=shellModel.Part(name='Proyectil', dimensionality=THREE_D, type=ANALYTIC_RIGID_SURFACE)
proyectilPart.AnalyticRigidSurfRevolve(sketch=proyectilProfileSketch)

#-----------------------------------------------------------------------
 
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