May 20, 2024 #1 jt2001 Electrical Apr 8, 2024 27 0 0 AU Hello, I have a fan hub I am looking to get an idea of the stresses it is under. Is there a way of appoximating the force normal to the surface given: - Air/medium density - Radial velocity - Fanblade geometery Kind regards, JT
Hello, I have a fan hub I am looking to get an idea of the stresses it is under. Is there a way of appoximating the force normal to the surface given: - Air/medium density - Radial velocity - Fanblade geometery Kind regards, JT
May 21, 2024 #21 rb1957 Aerospace Apr 15, 2005 15,593 0 36 CA greg, why would lift be related to centrifugal force ? why would lift not involve the density of air ? "Hoffen wir mal, dass alles gut geht !" General Paulus, Nov 1942, outside Stalingrad after the launch of Operation Uranus. Upvote 0 Downvote
greg, why would lift be related to centrifugal force ? why would lift not involve the density of air ? "Hoffen wir mal, dass alles gut geht !" General Paulus, Nov 1942, outside Stalingrad after the launch of Operation Uranus.
May 21, 2024 #22 GregLocock Automotive Apr 10, 2001 23,119 0 36 Orbiting a small yellow star It is and it isn't, Both are functions of v^2 as it happens. So centrifugal force is m*v^2/r and lift is 1/2*Cl*rho*A*v^2, where v=w*r Why both forces are proportional to v^2 is, I suspect, because both effects are inertial, but I'm not sure that is a great explanation. rho is 1.2 Cheers Greg Locock New here? Try reading these, they might help FAQ731-376 http://eng-tips.com/market.cfm? Upvote 0 Downvote
It is and it isn't, Both are functions of v^2 as it happens. So centrifugal force is m*v^2/r and lift is 1/2*Cl*rho*A*v^2, where v=w*r Why both forces are proportional to v^2 is, I suspect, because both effects are inertial, but I'm not sure that is a great explanation. rho is 1.2 Cheers Greg Locock New here? Try reading these, they might help FAQ731-376 http://eng-tips.com/market.cfm?