born2fly
Aerospace
- Mar 10, 2006
- 3
Hello,
I have an area out question.
On my (hypothetical) airplane control surface, some corrosion was discovered and trimmed out.
To determine the area loss/capability, is it the thickness of the material times the length (or width) of the trimmed surface?
So if the material was .063 inches thick, it would be Ftu(.063 x L), with Ftu used to determine a more conservative allowable.
Thank you in advance for answer my question.
I have an area out question.
On my (hypothetical) airplane control surface, some corrosion was discovered and trimmed out.
To determine the area loss/capability, is it the thickness of the material times the length (or width) of the trimmed surface?
So if the material was .063 inches thick, it would be Ftu(.063 x L), with Ftu used to determine a more conservative allowable.
Thank you in advance for answer my question.